URI Problem 1012 Solution in Java

Problem Details Link

Solution:

import java.util.Scanner;

/**
 * @Author : Muhammad Harun-Or-Roshid
 * @E-mail : md.parvez28@gmail.com
 * @Date   : Oct 6, 2016
 * @Time   : 8:38:17 PM
 */
public class Uri1012 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        double A,B,C;
        A = sc.nextDouble();
        B = sc.nextDouble();
        C = sc.nextDouble();
        //a) the area of the rectangled triangle that has base A and height C.
        double area_triangle = 0.5f*A*C;
        //b) the area of the radius's circle C. (pi = 3.14159) 
        double area_radius = 3.14159*C*C;
        //c) the area of the trapezium which has A and B by base, and C by height.
        double area_trapezium = ((A+B)/2)*C;
        //d) the area of ​​the square that has side B.
        double area_square = B*B;
        //e) the area of the rectangle that has sides A and B.
        double area_rectangle = A*B;
        
        System.out.printf("TRIANGULO: %.3f\n",area_triangle);
        System.out.printf("CIRCULO: %.3f\n",area_radius);
        System.out.printf("TRAPEZIO: %.3f\n",area_trapezium);
        System.out.printf("QUADRADO: %.3f\n",area_square);
        System.out.printf("RETANGULO: %.3f\n",area_rectangle);
    }
}