URI Problem Solution

Comments

Post a Comment

Popular posts from this blog

URI Problem 1094 Solution in Java

Problem Details  Link Solution: import java.util.Scanner; import java.text.DecimalFormat; import java.util.Scanner; /** * @Author : Muhammad Harun-Or-Roshid * @E-mail : md.parvez28@gmail.com * @Date : Oct 15, 2016 * @Time : 3:24:24 PM */ public class Uri1094 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String value; String values[]; int n = sc.nextInt(); int c = 0, r = 0, s = 0, total = 0; for (int i = 0; i = 1 && a
Read more

URI Problem 1099 Solution in Java

Problem Details  Link Solution: import java.util.Scanner; import java.util.Scanner; /** * @Author : Muhammad Harun-Or-Roshid * @E-mail : md.parvez28@gmail.com * @Date : Oct 17, 2016 * @Time : 7:44:30 PM */ public class Uri1099 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); for (int i = 0; i y) { int temp = x; x = y; y = temp; } for (int j = (x + 1); j
Read more

URI Problem 1012 Solution in Java

Problem Details  Link Solution: import java.util.Scanner; /** * @Author : Muhammad Harun-Or-Roshid * @E-mail : md.parvez28@gmail.com * @Date : Oct 6, 2016 * @Time : 8:38:17 PM */ public class Uri1012 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double A,B,C; A = sc.nextDouble(); B = sc.nextDouble(); C = sc.nextDouble(); //a) the area of the rectangled triangle that has base A and height C. double area_triangle = 0.5f*A*C; //b) the area of the radius's circle C. (pi = 3.14159) double area_radius = 3.14159*C*C; //c) the area of the trapezium which has A and B by base, and C by height. double area_trapezium = ((A+B)/2)*C; //d) the area of ​​the square that has side B. double area_square = B*B; //e) the area of the rectangle that has sides A and B. double area_rectangle = A*B; System.out.printf(...
Read more